A scooter maintains a pace of 1.45 minutes per mile, with fuel economy of 85 miles per gallon. How many seconds can it travel on 145 mL of fuel under these conditions

281s

Explanation:

Given parameters:

Speed of the scooter  = 1.45min per mile

Fuel economy of engine  = 85miles per gallon

Quantity of fuel  = 145mL

Unknown:

Time of travel with the volume of fuel given  = ?

Solution:

To solve this problem, we need to find the distance the fuel will last.

 Rate of fuel consumption by the engine  = 85miles per gallon

Convert 145mL to gallons;

                3785.41mL  = 1 gallon

               145mL will therefore give    = 0.038gallons

So;

   Distance covered  = 85miles per gallon  x 0.038gallons  = 3.23miles

From;

             Rate of travel  =  

       Time  = rate of travel x distance  = 1.45 minutes per mile x  3.23miles

     Time  = 4.7min

             1 min  = 60s

            4.7min  = 4.7 x 60 = 281s

the formula for the conversion of temperature from degree celsius to kelvin is:

the sample of water at is converted to kelvin temperature by using the above formula as:

on comparing the two samples of water at or we can say that at and at respectively. the difference between the temperatures of two samples of water is:

hence, one can say that the sample of water at is greater than the sample of water at by .