The energy for the following reaction was measured to be -1033.0 kJ/mol. Mg(g) + Cl(g) → MgCl₂(s).

Using this fact and data in the table below, calculate the enthalpy (in kJ/mol) required to separate the ions from the lattice for this reaction:

MgCl₂(s) → Mg²⁺(g) + 2Cl⁻(g).

Substance Ionization energy (kj/mol) electron affinity (kj/mol)

Mg(g) 737.8 0

Mg+ (g) 1450.7 --

Cl(g) 1251.2 -349.0

Please help me :C