A compound decomposes by a first-order process. If 13% of the compound decomposes in 60 minutes, the half-life of the compound is A12
B20
C299
D-18
E-5

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

it would be b. 6co2 + 6h2o --> c6h12o6 + 6o2