The molar mass of bismuth (\ce{Bi}BiB, i) is \pu{208.98 g/mol}208.98 g/mol208, point, 98, space, g, slash, m, o, l. Calculate the mass in grams of a sample of \ce{Bi}BiB, i containing \pu{7.35x10^23}7.35×10 23 7, point, 35, times, 10, start superscript, 23, end superscript atoms.

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

that's what i got you can count the number of atoms

the objects have the same charge.