How many grams of copper (II) fluoride (CuF2) are needed to make 9.66 liters of a 2.73 M solution?

Mass of Copper (II) fluoride needed = = 2677.87 g

Given

9.66 L of 2.73 M Copper (II) fluoride

Required

Mass

Solution

Molarity : mol solutes per liters of solution

M = n : V

n = mol solute

V = volume of solution

mol Copper (II) fluoride :

= M x V

= 2.73 M x 9.66 L

= 26.3718 mol

Mass Copper (II) fluoride :

= mol x MW CuF₂

= 26.3718 mol x 101,543 g/mol

= 2677.87 g

sorry i was late, but i don't know what assignment your talking about, i'm in flvs as well, im in earth space science. but u are behind pace bc every class should be in the 3's or 4'

2b2t

explanation:

2b2t