How many moles of magnesium nitrate are produced from 143.2 grams of nitric acid, HNO3? 2HNO3 + Mg(OH)2 = Mg(NO3)2 + 2H2O

1.14 mol

Explanation:

Given data:

Mass of HNO₃ react = 143.2 g

Moles of Mg(NO₃)₂ produced = ?

Solution:

Chemical equation:

2HNO₃ + Mg(OH)₂   →     Mg(NO₃)₂ + 2H₂O

Number of moles of HNO₃:

Number of moles = mass/molar mass

Number of moles = 143.2 g/ 63.01 g/mol

Number of moles = 2.273 mol

Now we will compare the moles of HNO₃  and Mg(NO₃)₂

                   HNO₃           :          Mg(NO₃)₂

                      2                :            1

                   2.273            :          1/2×2.273 = 1.14 mol

dynamic equilibrium is the answer.

1 is the answer to this problem