Which of the following is the metallic ion in sodium fluoride? 1. Na 1- 2. Na1 + 3. F 2- 4. F 2+

2. Na1 +

Explanation:

The formular for sodium fluoride is; NaF

The metal in sodium flouride is sodium.

Sodium belongs to group 1, hence would lose one electron when forming ions.

This is represented as;

Na+

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2