= 1 = 2
5
= 3
10
= 6
7
8
Write a balanced half-reaction for the reduction of gaseous oxygen (02) to liquid water
to liquid water (H2O) in acidic aqueous solution. Be sure to add physical state symbols
where appropriate.
a

A balanced half-reaction :

O₂(g)+ 4H⁺(aq)+ 4e⁻⇒2H₂O(l)

Further explanation

Given

Reduction of gaseous oxygen (O₂) to liquid water(H₂O)

Required

A balanced half-reaction

Solution

Step 1 : Equalize the number of elements by adding coefficients

Equates element O

O₂(g)⇒2H₂O(l)

Step 2 : Equalize H by adding H⁺ on the opposite side (the deficient area of H).

O₂(g)+ 4H⁺(aq)⇒2H₂O(l)

Step 3 : Equalized the charge using the addition of electrons (e⁻) along the H⁺ field.

O₂(g)+ 4H⁺(aq)+ 4e⁻⇒2H₂O(l)

Elias is almost correct. he just got it backwards.the correct answer is that it demonstrates elastic potential energy transforming into kinetic energy.

I’d have to say no because without oxygen in the water the fish would all be dead. so if you want to fish for dead fish, pick the ponds with the lowest oxygen concentrations.