Part b (r)–3-chloro-2-methylhexane will undergo a nucleophilic substitution reaction in the presence of sodium ethoxide and ethanol. complete the mechanism for the sn2 reaction and draw the products of the reaction. draw all missing reactants and/or products in the appropriate boxes by placing atoms on the grid and connecting them with bonds and including charges where needed. indicate the mechanism by drawing the electron-flow arrows on the molecules. arrows should start on an atom or a bond and should end on an atom, bond, or where a new bond should be created.

See answer below

Explanation:

To understand this, we need to make the reaction involved with the given configuration. Configuration R means that the substituents of the molecule, the priority order goes clockwise (From heaviest to lightest) so, if an Sn2 is ocurring in the reaction this means that the nucleophile, which in this case, is the sodium ethoxide will attack the molecule in the opposite side of the leaving group (which is the chlorine).

Also when this occurs, as Sn2 is a bimolecular reaction and is held in one step, it occurs an inversion in the configuration of the product. So, it's the innitial reactant was R, then the final product will be S.

The mechanism and product can be watched in the attached picture

Hope this helps.

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.