Ideal Gas Law Test 11 have 1.9 moles of gas held at a pressure of 5 atm and in a container with a volume of S0 liters, what is the temperature of the gas?
O 1603 K
O 273 K
O 0.0006
O 0.0006 K

T = 1603 K

Explanation:

Given data:

Number of moles of gas = 1.9 mol

Temperature of gas = ?

Pressure of gas = 5 atm

Volume of gas = 50 L

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

By putting values,

5 atm × 50 L = 1.9 mol × 0.0821 atm.L/ mol.K  × T

T = 250 atm.L / 1.9 mol × 0.0821 atm.L/ mol.K

T = 250 atm.L /0.156 atm.L/K

T = 1603 K

the correct option is c.

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explanation: