The products of the reaction CaF2 + Br2 → CaBr2 + F2 are formed by reacting calcium fluoride with bromine. If equal moles of each reactant were present, what would be the limiting reactant?

there is no limiting reactant.

Explanation:

Given that:

CaF₂  +  Br₂  >     CaBr₂  + F₂

From the above equation;

We can see that there is an equal number of moles in the reactant side of the equation.

i.e.

one mole of CaF₂  reacts with one mole of Br₂.

Thus, there is no limiting reactant.

it's c (engineer's do their work with mechanical stuff not on any living being)