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Mass of MgO = 36.27 g

Mg produced less number of moles of MgO it will act as limiting reactant while oxygen is present is in excess.

Explanation:

Given data:

Number of moles of Mg = 0.9 mol

Number of moles of O₂ = 1.1 mol

Number of moles of MgO = ?

Which reactant is in excess = ?

Which one is limiting reactant = ?

Solution:

Chemical equation:

2Mg + O₂    →        2MgO

now we will compare the moles of MgO with oxygen and magnesium.

                Mg           :          MgO

                  2            :           2

                  0.9         :         0.9

                O₂            :          MgO

                  1            :           2

                  1.1          :          2/1×1.1 = 2.2

Mg produced less number of moles of MgO it will act as limiting reactant while oxygen is present is in excess.

Mass of MgO:

Mass = number of moles × molar mass

Mass = 0.9 mol × 40.3 g/mol

Mass = 36.27 g