a. A container has a volume of 20 m3 and initially it contains 25 kg of methane at a pressure of 10 bar. Determine the specific volume in m3/kg. b. Add 5 kg of Ethane to the tank. What is the specific volume of the mixture in m3/kg

a. 0.80 m³/kg

b. 0.67 m³/kg

Explanation:

a.

Step 1: Given data

Volume of the container (V): 20 m³

Mass of methane (m): 25 kg

Step 2: Calculate the specific volume (v) of methane

Specific volume is defined as the number of cubic meters occupied by one kilogram of matter.

v = V/m

v = 20 m³/25 kg = 0.80 m³/kg

b.

Step 1: Calculate the mass of the mixture

m = m(methane) + m(ethane)

m = 25 kg + 5 kg = 30 kg

Step 2: Calculate the specific volume (v) of the mixture

v = V/m

v = 20 m³/30 kg = 0.67 m³/kg

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.