Calculate the mass of water produced when 1.43 g of butane reacts with excess oxygen. Express your answer to three significant figures and include the appropriate units. g

Explanation:

Hello!

In this case, since the combustion of butane is:

As there is an excess of oxygen, we can compute the mass of water by simply using the molar masses of butane and water and the 1:5 mole ratio between them as shown below:

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consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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