7. Sodium chloride is produced from its elements through a synthesis reaction. What mass of each reactant would be required to produce 25.0 mol of sodium chloride? Na + Cl2 → NaCl.

Mass of Cl₂  = 887.5 g

Mass of Na = 575 g

Explanation:

Given data;

Number of moles of sodium chloride produced = 25.0 mol

Mass of Na required = ?

Mass of Cl₂ required = ?

Solution:

Chemical equation:

2Na  +   Cl₂    →      2NaCl

now we will compare the moles of sodium chloride with both reactant.

                      NaCl         :          Na

                         2            :           2

                      25.0         :         25.0

                    NaCl          :          Cl₂

                       2             :           1

                      25.0        :          1/2 ×25.0 = 12.5 mol

Mass of Na:

Mass = number of moles × molar mass

Mass = 25.0 mol × 23 g/mol

Mass = 575 g

Mass of Cl₂:

Mass = number of moles × molar mass

Mass = 12.5 mol × 71 g/mol

Mass = 887.5 g

out of these options:

ability to burn paper

pure sodium reacting violently with water

the boiling point of water

helium does not tend to react with anything

i would say this is a physical property:

helium does not tend to react with anything

why? :

i said helium does not tend to react with anything because well, it reacts to ! but ability to burn paper, pure sodium reacting violently with water, & the boiling point of water are chemical or

physical properties: the properties of a substance that can be observed without changing the chemical makeup of the substance

chemical properties: properties of a substance relating to the chemical nature and reactivity of the substance

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g