What volume of hydrogen gas, when combined with nitrogen gas, is necessary to produce 16.0 L of ammonia gas (NH3)?

The volume of Hydrogen gas : 24 L

Given

16 L Ammonia(NH₃)

Required

The volume of Hydrogen gas

Solution

Reaction

N₂ + 3H₂ ⇒ 2NH₃

Avogadro's hypothesis:  

In the same T,P and V, the gas contains the same number of molecules  

So the ratio of gas volume will be equal to the ratio of gas moles  

V₁/n₁=V₂/n₂

From the equation, mol ratio of H₂ : NH₃ = 3 : 2, so volume of H₂ :

= 3/2 x volume of NH₃

= 3/2 x 16 L

= 24 L

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