Potassium hydroxide reacts with hydrochloric acid to form salt and water. a. Write the word equation and the balanced formulae equation for the above reaction.
b. What will happen if sodium hydroxide is used instead of potassium hydroxide ?
~ Thanks in advance !

a. KOH (aq) + HCl (aq) → KCl (s) + H₂O (l)

b. NaOH (aq) + HCl (aq) → NaCl (s) + H₂O (l)

General Formulas and Concepts:

Chemistry

Unit 0

Reading a Periodic TableWriting CompoundsPolyatomic Ions

Aqueous Solutions

States of matterSolubility RulesExplanation:

We are given "Potassium hydroxide reacts with hydrochloric acid to form salt and water."

a)

From the question, we can figure out 1.) if the reaction exists and 2.) if it does exist, then reaction prediction.

Potassium - K⁺Hydroxide (PAI) - OH⁻Potassium Hydroxide - KOHHydro - H⁺Chloric (Chlorine) - Cl⁻Hydrochloric acid (strong) - HCl

Remembering solubility rules, we have:

All common compounds of Group IA ions are solubleAll common chlorides, bromides, and iodides are mostly soluble (exceptions are Ag⁺, Pb²⁺, Cu⁺, Hg₂²⁺)

Therefore, we can conclude that both potassium hydroxide and hydrochloric are both aqueous solutions:

KOH (aq) + HCl (aq) → ? + ?

We are also given from the problem that the reaction produces a salt and water.

Molecular Formula of water - H₂O

We also use the double replacement reaction to do reaction prediction of the proposed salt:

KOH (aq) + HCl (aq) → KCl (s) + H₂O (l)

Hence, this is our answer to a.).

b.)

We are given that we switch the compound KOH (potassium hydroxide) with sodium hydroxide.

Sodium - Na⁺Hydroxide (PAI) - OH⁻Sodium Hydroxide - NaOH

We can use the same steps as a.) to figure out our new reaction. Since we already know that Group IA compounds are soluble, we know that NaOH is soluble:

NaOH (aq) + HCl (aq) → ? + H₂O (l)

Following the same steps, we can simple do a double replacement reaction prediction to find the missing salt:

NaOH (aq) + HCl (aq) → NaCl (s) + H₂O (l)

We see that we would still be able to produce a [different] salt and the reaction does exist/run. And we have our final answer for b.).

Note:

While the salts produced (KCl and NaCl) are solids, they are soluble in water. Since we are running only a forward reaction, we know that we are producing a solid and liquid water. Usually, we would probably see these reactions in equilibrium (represented with a ⇆).

This also delves into the concepts of saturation.

jjj

Forgot the question hahaha