2Sr(s)+O2(g)→2SrO(s) calculate how many grams of the product form when 16.4 of Sr completely reacts.

Assume that there is more than enough of the other reactant.

Mass = 19.68 g

Explanation:

Given data:

Mass of product formed = ?

Mass of Sr  16.4 g

Solution:

Chemical equation:

2Sr + O₂      →    2SrO

Number of moles of Sr:

Number of moles = mass /molar mass

Number of moles = 16.4 g/ 87.62 g/mol

Number of moles = 0.19 mol

Now we will compare the moles of Sr with SrO.

                     Sr           :         SrO

                      2           :           2

                    0.19        :         0.19

Mass of Sr:

Mass = number of moles × molar mass

Mass = 0.19 mol × 103.62 g/mol

Mass = 19.68 g

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