How is the oxidation state of a transition metal determined from the chemical formula?

A. A superscript on the transition metal identifies its oxidation state

in the formula.

B. The subscript of the transition metal in the formula identifies its

oxidation state.

C. A Roman numeral placed after the transition metal identifies its

oxidation state.

D. The total charge of the negative ion identifies the oxidation state

of the transition metal.

C. A Roman numeral placed after the transition metal identifies its

oxidation state.

Explanation:

A. A superscript on the transition metal identifies its oxidation state

in the formula.

This is wrong! Superscript are usually not written in formula of compound and for those that have superscripts, it refers to the oxidation number of the compound as a whole.

B. The subscript of the transition metal in the formula identifies its

oxidation state.

This is wrong! Subscripts shows how many atoms of the element is present.

C. A Roman numeral placed after the transition metal identifies its

oxidation state.

This is correct! Examples include; manganese (II) oxide, Potassium manganate (VII) etc

D. The total charge of the negative ion identifies the oxidation state

of the transition metal.

This is wrong! Because there are cases of other metals or cations being present in the compound aside the transition metal

answer: -

reaction:

na + cl ⇌ nacl

balanced chemical equation:

na + 2cl ⇌ nacl2

sodium + clorine goes to form sodium chloride (table salt).

the product is nacl2.

and the reactants are na and cl.

(note: if you don’t know what ⇌ means, read below: -

⇌(double head arrow) means reversible reaction).