Lithium diorganocopper (Gilman) reagents are prepared by treatment of an organolithium compound with copper(I) iodide. Decide what lithium diorganocopper (Gilman) reagent is needed to convert 1-bromopropane into 1-hexene.

Explanation:

Gilman reagent is also known as the Lithium organocuprates. They are used as nucleophiles in the organic synthesis.

Gilman reagent is used for C - C bond formation.

                                                            H    H    H

                                                             |      |      |

              -----→     H  - C -- C -- C -- C =

           (1 bromo propane)                   |      |     |       |

                                                           H     H   H     H

                                                             (1 pentene)

Normally in C--C formation by Gilman reagent, the following reactions takes place :

R -- Br   +    R--R' + R' Cu + Li Br

In 1 pentene, i.e.

(from 1 bromo    (from Gilman reagent)

      propane)

So Gilman reagent is

Organo lithium compound is

electron microscopy and scanning tunneling microscopes gives us a greater understanding of atoms by being able to see the atom itself, and lets us see some atomic reactions.

explanation:

the answer is 1260

you spend 7 hours in school for 1 school day with 5 school days in 1 school week with 36 school weeks in a school year.

7*5*36= 1260 it's all about multiplying