A student obtained a test tube with a suspension of white, slightly soluble calcium hydroxide in water. This system was at equilibrium as represented by the following equation:. Ca(OH)2(s)Ca2(aq)+ 20H(aq)
Write the equilibrium constant expression for this reaction.

K = [Ca²⁺] [OH¯]² / [Ca(OH)₂]

Explanation:

Equation for the reaction is given below:

Ca(OH)₂(s) —> Ca²⁺(aq) + 2OH¯(aq)

Equilibrium constant =?

Equilibrium constant (K) for a reaction is simply the ratio of the concentration of the products raised to their coefficient to the concentration of the reactants raised to their coefficient.

Thus, we can write the equilibrium constant (K) for the above reaction as follow:

Ca(OH)₂(s) —> Ca²⁺(aq) + 2OH¯(aq)

K = [Ca²⁺] [OH¯]² / [Ca(OH)₂]

rosa was looking for patterns to predict the products of chemical reactions. she recorded three similar decomposition reactions in the table.she should record 2licl + 3o2.

in the last row of the table. it is the thermal decomposition of chlorate lithium, hence, she should record these products as: lithium chloride ( 2licl ) and oxygen ( 3o2 )   2 > 2 licl + 3o2.