What volume, IN MILLILITERS, of 5.0M HCl solution is required to react with 3.00 g or magnesium metal?

The volume of HCl = 2.10⁴ mL

Given

5.0 M(mol/L) HCl solution

3 g of Mg

Required

Volume of HCl

Solution

Reaction

Mg + 2HCl ⇒ MgCl₂ + H₂

mol of Mg (Ar=24 g/mol) :

mol = mass : Ar

mol = 3 : 24

mol = 0.125

From the equation, mol ratio of Mg : HCl = 1 : 2, so mol HCl :

= 2/1 x mol Mg

= 2 x 0.125

= 0.25

Molarity : mol solute per liters solution

M = m x V

V = M : m

V = 5 mol/L : 0.25

V = 20 L = 2.10⁴ mL

increased stability in the completion of fluorine's outer shell.

each  column  of the  table  is called a group. elements in a group share similar properties. groups are  read  from  top  to  bottom. metal. metalloid. nonmetal. solid. liquid. gas. fe. hg. o.  2. 3. 4. 5. 6. 7. 8. 9.  2. beryllium. 9.012. 4.  sodium. 22.990.  11. 3.  magnesium. 24.305.  12.  potassium. 39.098.  19. 4.  calcium. 40.078.  20. i guess  i