How many moles of gas would be present in a gas trapped within a 0.1 L vessel at 25.0 °C at a pressure of 2.50 atm?

Number of moles  = 0.01 mole

Explanation:

Given data:

Volume of gas = 0.1 L

Number of moles = ?

Temperature of gas = 25.0°C

Pressure of gas = 2.50 atm

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will convert the temperature.

25+273K = 298 K

by putting values,

2.50 atm × 0.1 L = n × 0.0821 atm.L/ mol.K  × 298 K

0.25 atm.L = n × 24.47atm.L/ mol

n = 0.25 atm.L /24.47atm.L/ mol

n = 0.01 mol

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b) mutualism

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