How many grams of water are produced when 37.7 g of hydrogen peroxide (H2O2) decomposes into oxygen gas and water?

Mass of water produced = 19.8 g

Explanation:

Given data:

Mass of hydrogen peroxide = 37.7 g

Mass of water produced = ?

Solution:

Chemical equation:

2H₂O₂      →        2H₂O  + O₂

Number of moles of H₂O₂:

Number of moles = mass/molar mass

Number of moles = 37.7 g/ 34 g/mol

Number of moles = 1.1 mol

Now we will compare the moles of H₂O₂ and H₂O from balance chemical equation in order to determine the moles of water formed.

                                   H₂O₂      ;           H₂O

                                      2         :             2

                                     1.1         :          1.1

Mass of water formed:

Mass = number of moles × molar mass

Mass = 1.1 mol × 18 g/mol

Mass = 19.8 g

answer: the figure is attached herewith.

step-by-step explanation:   we are given to sketch a unit circle and label the terminal points corresponding to

in the attached figure, we have drawn a unit circle, with centre at o(0,0) and radius 1 unit. we have labelled the points a, b, c, d and e corresponding to the angles below

∠aox = 60°,

∠box = 120°,

∠cox = 180°,

∠dox = 240°,

∠eox = 300°.

and the coordinates are a(0.5,1), b(-0.5,1), c(-1,0), d(-0.5,-1) and e(0.5,-1).

thus, the answer is complete.