Can I please Get Help with This Question ‍♂️?

621.41 grams

Explanation:

First of all, to find the mass. You have to use the molar mass of AlBr3 to convert from moles to mass.

Second of all, find the molar mass of AlBr3.

Al = 27.0 amu

Br = 79.9 amu

They are 3 bromine atoms and 1 aluminum atom.

So you do this

27.0 + 79.9(3) = 266.7

The molar mass is 266.7 g/mol

Third of all, use dimensional analysis to show your work.

2.33 moles of AlBr3 * 266.7 g/mol / 1 mol

Moles cancel out.

2.33 x 266.7 = 621.411

Your teacher though said to round digits after the decimal point instead of using sig figs.

621.411 rounds to 621.41

So the final answer is 621.41 grams(don't forger the units).

The substance formula is just AlBr3.

That's all.

Hope it helped!

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