An ideal gas system undergoes an isovolumetric process in which 20J of energy is added as heat to the gas. What is the change in the systems internal energy

the change in the system internal energy is 20 J

Explanation:

The computation of the change in the system internal energy is as follows:

Since the volume remains constant so the work done would be zero

Now the change in the internal energy is

= Heat given to system - work done

= 20 J - 0

= 20 J

hence, the change in the system internal energy is 20 J

The same is to be considered

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole