Determine the mass of 21.05 moles of iron(III) sulfide.

The mass of 21.05 moles of iron(III) sulfide is 4,372.085 grams.

Explanation:

Iron (III) sulfide is a chemical compound with the formula Fe₂S₃.

Being the molar mass of the elements:

then the molar mass of iron sulfide (III) is:

Fe₂S₃= 2* 55.85 g/mole + 3* 32 g/mole=  207.7 g/mole

Molar mass is the amount of mass that a substance contains in one mole. Then the rule of three can be applied: if in 1 mole of iron (III) sulfide there are 207.7 grams, in 21.05 moles how much mass is there?

mass= 4,372.085 grams

The mass of 21.05 moles of iron(III) sulfide is 4,372.085 grams.

answer:

the answer is 6 valence electrons.

explanation:

valence is the # of electrons on the outer most shell of an atom.

oxygen has 6.

although, the valency of oxygen is 2, because it only needs to make 2 covalent bonds, or gain 2 electrons, to achieve the stable octet configuration of a noble gas.

that's it!

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