how much energy would be lost by 23 g of water if it was heated until it was 78 degrees celsius and then allow to cool down to 27 degrees celsius

Q = -4903.14 j

Explanation:

Given data:

Mass of water = 23 g

Initial temperature = 78°C

Final temperature = 27°C

Heat lost = ?

Solution:

Specific heat capacity of water is 4.18 J/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT =  27°C - 78°C

ΔT = -51°C

Q = 23 g × 4.18 J/g.°C  × -51°C

Q = -4903.14 j (negative sign shows heat is released)

in chemistry, adhesion and cohesion are attractive forces that exist between molecules. they hold the molecules together from each other. they are different in that adhesive force exists between molecules of different substance while cohesive force happens between molecules of same substance.

adhesion between water and glass causes water molecules at the edge of water and glass interface to climb up the wall in a narrow glass tube. this is called capillary action. cohesion is what gives glass its shape and causes water to form a droplet.