A gas was at STP. If the pressure increased to 3.5 atm, what would the new
temperature be?

T₂  = 956.0 K

Explanation:

Given data:

Initial temperature = 273.15 K

Initial pressure = 1 atm

Final pressure = 3.5 atm

Final temperature = ?

Solution:

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

1 atm / 273.15 K = 3.5 atm / T₂

T₂  = 3.5 atm ×273.15 K / 1 atm

T₂  = 956.0 atm. K /  1 atm

T₂  = 956.0 K

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