a laboratory procedure calls for making 510.0 mL of a 1.6 M KNO3 solution. How much KNO3 in grams is needed

82.416 g of KNO ₃  is needed to produce 510.0 mL of a 1.6 M KNO ₃ solution.

Explanation:

Since molarity is the number of moles of solute that are dissolved in a given volume, calculated by dividing the moles of solute by the volume of the solution, the following rule of three can be applied: if in 1 L (1,000 mL) of KNO₃ there are 1.6 moles of the compound present, in 510 mL how many moles will there be?

moles= 0.816

Being the molar mass of the elements:

K: 39 g/moleN: 14 g/moleO: 16 g/mole

So the molar mass of the compound KNO₃ is:

KNO₃= 39 g/mole + 14 g/mole + 3*16 g/mole= 101 g/mole

Now I can apply the following rule of three: if in 1 mole of KNO₃ there are 101 g, in 0.816 moles how much mass is there?

mass= 82.416 grams

82.416 g of KNO ₃  is needed to produce 510.0 mL of a 1.6 M KNO ₃ solution.

It is a body of knowledge gained  using  inquiry and experimentation 

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