A chemist reacts 35 g of MgCl, with excess KOH according to the reaction below. How much Mg(OH)2 would be
produced if the reaction goes to completion?
MgCl2 + 2KOH – Mg(OH)2 + 2KCI

Mass = 21.58 g

Explanation:

Given data:

Mass of MgCl₂ = 35 g

Mass of Mg(OH)₂ produced = ?

Solution:

Chemical equation:

MgCl₂ + 2KOH    →     Mg(OH)₂ + 2KCl

Number of moles of MgCl₂:

Number of moles = mass/molar mass

Number of moles = 35 g/ 95.2 g/mol

Number of moles = 0.37 mol

now we will compare the moles of MgCl₂ and Mg(OH)₂

                MgCl₂         :        Mg(OH)₂

                   1               :            1

                 0.37           :        0.37

Mass of  Mg(OH)₂ :

Mass = number of moles × molar mass

Mass = 0.37 mol × 58.32 g/mol

Mass = 21.58 g

< > according to newton's third law of motion, forces always act in equal but opposite pairs. another way of saying this is for every action, there is an equal but opposite reaction.< >

"record the time to complete a chemical reaction" would most likely be part of a lab procedure.