g Determine the oxidation state for each of the elements below. ... The oxidation state of ... phosphorus ... in ... phosphorous tribromide PBr3 ... is ... . The oxidation state of nitrogen in nitrogen gas N2 is . The oxidation state of arsenic in arsenic acid H3AsO4 is .

- P in PBr3 is +3.

- N in N2 is 0.

- As in H3AsO4 is +5.

Explanation:

Hello!

In this case, since the determination of the oxidation states is performed by using the well-known charge balances, we can proceed as shown below:

- P in PBr3: Here, bromide ions have an oxidation state of -1, so we follow:

Thus, the oxidation state is +3.

- N in N2: Here, since nitrogen is bonding with nitrogen and it is neutral, we infer its oxidation state is 0.

- As in H3AsO4: Here, oxygen is -2 and hydrogen +1, so we follow:

Thus, the oxidation state is +5.

Best regards!

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

that tool would be a compass