g What amounts of 45% pure silver and 50% pure silver should be mixed to obtain 14 grams of 46% pure silver

11.2g of the 45% pure silver and 2.8g of the 50% pure silver.

Explanation:

14g of 46% pure silver contains:

14g*46% = 6.44g of silver are required. Thus, we can write:

6.44 = X*50% + Y*45% (1)

Where X is the mass of 50% pure silver and Y the mass of 45% pure silver.

As the mass of the sample must be 14g:

14g = X + Y (2)

Replacing (2) in (1):

6.44 = (14-Y)*50% + Y*45%

6.44 = 7 - 0.5Y + 0.45Y

-0.56 = -0.05Y

Y = 11.2g of the 45% pure silver

And:

14g-11.2g = X

X =

2.8g of the 50% pure silver

answer: -

reaction:

na + cl ⇌ nacl

balanced chemical equation:

na + 2cl ⇌ nacl2

sodium + clorine goes to form sodium chloride (table salt).

the product is nacl2.

and the reactants are na and cl.

(note: if you don’t know what ⇌ means, read below: -

⇌(double head arrow) means reversible reaction).