62.4 mL of an HNO3 solution were titrated with 56.25 mL of a 0.235 M
KOH solution to reach the
equivalence point. What is the
molarity of the HNO3 solution?

The  molarity of the HNO₃ solution : 0.212 M

Given

62.4 mL HNO₃

56.25 mL of a 0.235 M  KOH

Required

Molarity HNO₃

Solution

Titration formula

M₁V₁n₁=M₂V₂n₂

1= HNO₃, 2 = KOH

n = acid base valence (amount of H⁺/OH⁻ released,for HNO₃ and KOH = 1)

Input the value :

M₁ x 62.4 x 1 = 0.235 x 56.25 x 1

m=9

step-by-step explanation:

periodic trends is an atom that gets larger as the number of electronic shells increase, the radius of atoms increases as you go down a certain group in the periodic table of elements. in general, the size of an atom will decrease as you move from left to right of a certain period.