Rico is doing an experiment. He makes a solution of calcium carbonate in a beaker of 200 mL of water at room temperature (25 °C). He adds a small amount of lemon juice to the solution and a chemical reaction begins. Rico reduces the temperature of the solution by 10 °C by adding ice. As the solution cools, what will happen to the chemical reaction?

The question is incomplete, the complete question is;

Rico is doing an experiment. He makes a solution of calcium carbonate in a beaker of 200 mL of water at room temperature (25 °C). He adds a small amount of lemon juice to the solution and a chemical reaction begins. Rico reduces the temperature of the solution by 10 °C by adding ice. As the solution cools, what will happen to the chemical reaction?  

A.The chemical reaction will stop suddenly.

B.There will be no change in the rate of the chemical reaction.

C.The chemical reaction will slow as the water cools.

D.The speed of the chemical reaction will increase as the water cools.

C.The chemical reaction will slow as the water cools.

Explanation:

The rate of a chemical reaction is dependent on the temperature of the reaction system. This derives directly from the collision theory of chemical reaction.

The higher the temperature of the system, the more frequently the particles collide and the faster the rate of reaction.

As the temperature is decreased, the rate of reaction decreases simultaneously. Therefore, as Rico decreases the temperature from 25 degrees to 10 degrees, the rate of reaction decreases accordingly.

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

pie chart because it is in percents ( % )