calculate the mass of Ag3AsO4 that would be produced if enough AgNO3 solution is added to precipitate all of the AsO43- in the 100.0 mL of the 0.1 M Na3AsO4 solution. Record this amount on your report sheet.

5 g

Explanation:

Step 1: Write the balanced equation

3 AgNO₃(aq) + Na₃AsO₄(aq) ⇒ Ag₃AsO₄(s) + 3 NaNO₃(aq)

Step 2: Calculate the reacting moles of Na₃AsO₄

100.0 mL of 0.1 M Na₃AsO₄ react.

0.1000 L × 0.1 mol/L = 0.01 mol

Step 3: Calculate the moles of Ag₃AsO₄ formed from 0.01 moles of Na₃AsO₄

The molar ratio of Na₃AsO₄ to Ag₃AsO₄ is 1:1. The moles of Ag₃AsO₄ formed are 1/1 × 0.01 mol = 0.01 mol.

Step 4: Calculate the mass corresponding to 0.01 moles of Ag₃AsO₄

The molar mass of Ag₃AsO₄ is 461.61 g/mol.

0.01 mol × 461.61 g/mol = 5 g

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your answer would be a. 12.5 kg