A mixture of 1.20 mols He, 2.40 mols Ne, 4.80 mols Kr, and 0.60 mols Ar has a total pressure of 600.0 mm Hg. What is the partial pressure of the Kr? Show all work to receive full credit.

The partial pressure of the Kr is 320 mm Hg.

Explanation:

According to Raoult's Law , the partial pressure of each component in the solution is equal to the total pressure multiplied by its mole fraction. It is mathematically expressed as

where, = partial pressure of component A

= mole fraction of A

= total pressure

mole fraction of Krypton =

Thus partial pressure of the Kr is 320 mm Hg

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