Chemistry, 02.01.2021 16:30 jessica2138

Calculate the molality of a 5.73 M ethanol (C2H5OH) solution whose density is 0.9327 g/mL.

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Considering the definition of molality , you obtain that the molality of a 5.73 M ethanol (C₂H₅OH) solution whose density is 0.9327 g/mL is 8.57 $\frac{moles}{kg}$ .

Molality is the ratio of the number of moles of any dissolved solute to kilograms of solvent.

The Molality of a solution is determined by the expression:

$Molality=\frac{number of moles of solute}{kilogramof solvent}$

You have a 5.73 M ethanol (C₂H₅OH) solution whose density is 0.9327 g/mL.

Molarity is the number of moles of solute that are dissolved in a certain volume.

In this case, taking into account that the volume considered is 1 L, the number of moles of solute is 5.73 moles.

On the other side, density is the ratio of the weight (mass) of a substance to the volume it occupies. So, being 1 mL= 0.001 L, 0.9327 g/mL means that you have 0.9327 grams per 1 mL or 932.7 g per 1 L.

So, being the mass of solution calculated as number of moles multiplied by the molar mass, and being the mass of the solution 932.7 grams in 1 L, the mass of water is:

Mass of solvent = mass of solution - mass of solute

Mass of solvent = mass of solution - number of moles× molar mass

Mass of solvent = 932.7 g - 5.73 mol× 46.068 g/mol

Mass of solvent = 932.7 g - 263.97 g

Mass of solvent = 668.73 g= 0.66873 kg

Then, the molality can be calculated as:

$Molality=\frac{5.73 moles}{0.66873 kg}$

Solving:

molality= 8.57 $\frac{moles}{kg}$

Finally, the molality of a 5.73 M ethanol (C₂H₅OH) solution whose density is 0.9327 g/mL is 8.57 $\frac{moles}{kg}$ .

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Answer from: yaya6940

Molality = 8.57 m

Explanation:

Given data:

Molarity of solution = 5.73 M

density = 0.9327 g/mL

Molality of solution = ?

Solution:

Molality = moles of solute / kg of solvent.

Kg of solvent:

Mass of 1 L solution = density× volume

Mass of 1 L solution = 0.9327 g/mL × 1000 mL

Mass of 1 L solution = 932.7 g

Mass of solute:

Mass of 1 L = number of moles × molar mass

Mass = 5.73 mol × 46.068 g/mol

Mass = 263.97 g

Mass of solvent:

Mass of solvent = mass of solution - mass of solute

Mass of solvent = 932.7 g - 263.97 g

Mass of solvent = 668.73 g

In Kg = 668.73 /1000 = 0.6687 Kg

Molality:

Molality = number of moles of solute / mass of solvent in Kg

Molality = 5.73 mol / 0.6687 Kg

Molality = 8.57 m

Answer from: Quest

when [oh-] is 10-5 m, and [h3o+] is 10-9 m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.

Answer from: Quest

it would be d. henry moseley

hope this !

and sorry if i'm late. have a good rest of your day! : d

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Calculate the molality of a 5.73 M ethanol (C2H5OH) solution whose density is 0.9327 g/mL....

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