g is the maximum number of grams of ammonia, NH , which can be obtained from the reaction of 10.0 g of H and 80.0 g of N

56.67 g of NH₃.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

N₂ + 3H₂ —> 2NH₃

Next, we shall determine the masses of N₂ and H₂ that reacted and the mass of NH₃ produced from the balanced equation. This is illustrated below:

Molar mass of N₂ = 14 × 2 = 28 g/mol

Mass of N₂ from the balanced equation = 1 × 28 = 28 g

Molar mass of H₂ = 1 × 2 = 2 g/mol

Mass of H₂ from the balanced equation = 3 × 2 = 6 g

Molar mass of NH₃ = 14 + (3×1) = 14 + 3 = 17 g/mol

Mass of NH₃ from the balanced equation = 2 × 17 = 34 g

SUMMARY:

From the balanced equation above,

28 g of N₂ reacted with 6 g of H₂ to produce 34 g of NH₃

Next, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

28 g of N₂ reacted with 6 g of H₂.

Therefore, 80 g of N₂ will react with = (80 × 6)/28 = 17.14 g of H₂.

We can see from the calculation made above that a higher mass (i.e 17.14 g) of H₂ than what was given (i.e 10 g) is required to react completely with 80 g of N₂. Thus, H₂ is the limiting reactant and N₂ is the excess reactant.

Finally, we shall determine the maximum mass of ammonia (NH₃) produced from the reaction.

To obtain the maximum mass of NH₃, the limiting reactant will be used because all of it is consumed in the reaction.

The limiting reactant is H₂ and the maximum mass of NH₃ can be obtained as follow:

From the balanced equation above,

6 g of H₂ reacted to produce 34 g of NH₃.

Therefore, 10 g of H₂ will react to produce = (10 × 34)/6 = 56.67 g of NH₃.

Therefore, 56.67 g of NH₃ is produced from the reaction.

the electronic configuration of an atom with eight electrons is 1s²2s²2p⁴. the orbital diagrams are shown in the figure.

as per the hunds rule:

1. electrons tend to avoid being in the same orbital as per as practicable.

2. electrons in different orbitals of the same energy will have their spin parallel.

this can be illustrated from the multiplicity of the orbitals of the atom. as there are four electrons in the p orbital and p orbital has 3 sub-shells. the electrons can be fed in different ways as shown in the figure but the correct orbital diagram will be as per the hunds rule.