Help with this asap please

ΔH rxn = 434.7 kJ

Given

C+O₂⇒CO₂   ΔH=-393.5 (reaction 1)

2CO+O₂⇒2CO₂  ΔH=-566 (reaction 2)

2H₂O⇒2H₂+O₂ ΔH=483.6 (reaction 3)

Required

ΔH rxn

Solution

Reaction 1 : no change

C+O₂⇒CO₂   ΔH=-393.5

Reaction 2 : the reaction is reversed and divided by 2

CO₂⇒ CO+1/2O₂ ΔH=-283

Reaction 3 : divided by 2

H₂O⇒H₂+1/2O₂ ΔH=241.8

C+H₂O⇒CO + H₂ ΔH rxn= -434.7 kJ

8 m/s because for him to get the same amount of energy as ray is putting out, bobby, who weighs half as much as ray, needs to run twice as fast.