A 1.00 L sample of a gas has a mass of 1.92 g at STP. What is the molar mass (molecular weight) of the gas

Given:

Now,

Number of moles will be:

=

=

hence,

The molar mass,

=

By putting the values,

=

=

Thus the answer above is correct.

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The answer is below

Explanation:

Avogadro stated that "Equal volumes of all gases at the same temperature and pressure contain the same number of molecules". Hence at standard temperature and pressure 1 mole of a gas occupies 22.4 liters of volume.

1 mol = 22.4 liters

Given a gas with 1 L and mass of 1.92 g at STP.

number of moles = 1 L / (22.4 L / mol) = 0.0446 mol

The molar mass = mass of gas / number of moles

molar mass = 1.92 g / 0.0446 mol

molar mass = 43.008 g / mol