The molar heat capacity is represented in the temp range 298 to 400 k by the emprical expression 14.73+0.1272 calculate the enthalpy if formation of ethane at 350 k from its valu at 298 k

Explanation:

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In this case, since the enthalpy of formation of ethane at 298 K is about -84 kJ/mol, via the Kirkoff's law, we can compute it a 350 K as shown below:

It means we can integrate to get:

Now, we can plug in the enthalpy of formation in consistent units to obtain:

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answer; economic order quantity;

it would be b. 6co2 + 6h2o --> c6h12o6 + 6o2