for each pair of compounds below , identify the one that would be expected to have more ionic character. explain you choice. (a)NaBr or HBr (b)BrCl or FCl

a)NaBr

b)FCl

Explanation:

To identify which compound is more ionic we will calculate the electronegativity difference.

A) NaBr

Electronegativity of Na = 0.93

Electronegativity of Br = 2.96

Electronegativity difference = 2.96- 0.93 = 2.03

HBr

Electronegativity of H = 2.2

Electronegativity of Br = 2.96

Electronegativity difference = 2.96 - 2.2 = 0.76

NaBr have more ionic character because of large electronegativity difference.

B) BrCl

Electronegativity of Cl = 3.16

Electronegativity of Br = 2.96

Electronegativity difference = 3.16 - 2.96 = 0.2

FCl

Electronegativity of F = 3.98

Electronegativity of Br = 2.96

Electronegativity difference = 3.98 - 2.96 = 1.02

FCl have more ionic character because of large electronegativity difference.

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