To what temperature does a 250 mL cylinder containing 0.1 MOLHE need to be cooled in order for the pressure to be 253.2 5 K PA

we use the formula

pV=nRT

we convert Kilo Pascals to mmHg

253.25 KPa=253250 pascals

1mmHg is equal to 133.322 pascals

xmmHg are equal to 253250pascals

x=253250/133.322=1900mmHg

now we convert mmHg to atmospheres

1 atmosphere is equal to 760mmHg

x atmospheres are equatl to 1900mmHg

x=1900/760=2.5 atmospheres

in the formula:

pV=nRT

p-pressure

V-volume

n-number of moles

R-ideal constant of gases

T-temperature

the only missing variable is temperature since we know that  R=0.082

250ml=0.25L

0.25*2.5=0.1*0.082T

T=0.625/0.0082=76.219K