Calculate the mass in gram of binormal solution in NAOH

80 grams

Explanation:

Normality is one of the units of concentration and it is derived by dividing the gram or mole equivalent of the solute in a solution by the volume (in liters) of the solution.  

The equivalent weight of NaOH is derived by dividing the molecular weight of the compound by 1. Hence, the equivalent weight of NaOH in 1 normal solution is 40/1 = 40 g.

If 1 normal NaOH solution contains 40 g of NaOH in 1 liter of the solution, then a binormal (2 normal) solution of NaOH would contain;

   2 x 40 = 80 g of NaOH.

each chemical family is represented as a group or column on the periodic table. based on chemical properties, there are 6 types of chemical families. group 1 represents alkali metals, group 2 represents alkaline earth metals, groups 3 to 12 represent transition metals, groups 13 to 16 represent non-metals and other metals, group 17 represents halogens and group 18 represents noble gases.