A chemist determines by measurements that moles of bromine liquid participate in a chemical reaction. Calculate the mass of bromine liquid that participates. Be sure your answer has the correct number of significant digits.

This question is incomplete as it lacks the number of moles of Bromine. The complete part is as follows: 0.0900 moles of bromine liquid participate in a chemical reaction.

The answer is 7.191g

Explanation:

The number of moles in a substance can be calculated thus;

moles = mass/molar mass

Atomic mass of Bromine = 79.9g/mol

According to the question, the chemist determines by measurements that 0.0900 moles of bromine liquid participate in a chemical reaction. To calculate the mass of bromine liquid that participates, we say;

Mass = moles × molar mass

Mass = 0.0900 × 79.9

Mass = 7.191g

Therefore, 7.191g of Bromine will participate in the chemical reaction.