2. what is the molarity of a 300ml solution which is 25%by mass H2S04? the solutions mass is 353.4g

3 M

Explanation:

Molarity is calculated by dividing the moles of the solute by the liters of solution. In this problem, we are given that the mass of the solution is 353.4 g and that the mass of the solute (H2SO4) is 25% of this.

Thus, you get that the mass of the solute is 88.35 g.

Next, you must convert the mass of the solute into moles. You must use the periodic table to find the molar mass of the solute in order to do the conversion.

Thus, you get that the number of moles of solute is 0.90.

Molarity is then = 0.90 mol/.300 L = 3 M.

3 M

Explanation:

0.90 mol/.300 L = 3 M.

metric time was an attempt to create a standard unit of time based off of 10, but it never took off an is not included in the metric system (si)