if you start with 55 grams of sodium flouride naf how many grams of magnesium fluride mgf2 will be produced

Mass of MgF₂ formed = 40.5 g

Explanation:

Given data:

Mass of NaF = 55 g

Mass of MgF₂ formed =  ?

Solution:

Chemical equation:

2NaF  +  Mg      →     MgF₂ + 2Na

Number of moles of NaF:

Number of moles = mass/molar mass

Number of moles = 55 g / 41.98 g/mol

Number of moles = 1.3 mol

now we will compare the moles of sodium fluoride with magnesium fluoride.

                     NaF       :          MgF₂

                       2          :             1

                     1.3          :        1/2×1.3 =  0.65 mol

Mass of magnesium fluoride:

Mass = number of moles × molar mass

Mass = 0.65 mol × 62.3 g/mol

Mass = 40.5 g