You mix 999 mL pure water and 1 mL of 2.0 M NaOH. Calculate the pH of the resulting solution. (assume the total volume is 1.0 L). a. 0.3
b. 0.7
c. 2.7
d. 11.3
e. 13.7

D => 11.3

Explanation:

(Molarity x Volume) diluted = (Molarity x Volume) concentrate

=> [NaOH] = (1/999)(2M) = 0.002M in NaOH = 0.002M OH⁻

pOH = -log[OH⁻] = -log(0.002) = 2.7

pH = 14 - pOH = 14 - 2.7 = 11.3

2b2t

explanation:

2b2t

elements make up everything, and they combine to make compounds.

the answer is c