A compound has an empirical formula CH2 and a molecular mass of 70.1 amu. What is the molecular formula?

Molecular formula = C₅H₁₀

Explanation:

From the question given above, the following data were obtained:

Empirical formula of compound => CH₂

Molar mass of compound = 70.1 amu

Molecular formula of compound =...?

The molecular formula of a compound is usually a multiple (n) of the empirical formula i.e

Molecular formula = [CH₂]ₙ

Thus, to obtain the molecular formula of the compound, we must first determine the value of n. The value of n can be obtained as follow:

[CH₂]ₙ = 70.1

[12 + (2×1)]n = 70.1

[12 + 2]n = 70.1

14n = 70.1

Divide both side by 14

n = 70.1 / 14

n = 5

Molecular formula = [CH₂]ₙ

Molecular formula = [CH₂]₅

Molecular formula = C₅H₁₀

Thus, the Molecular formula of the compound is C₅H₁₀.

it should be all of them because it asks if you included all of those in your answer

explanation:

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the atomic number of carbon is six, which means that a carbon atom has six protons. carbon has three naturally occurring isotopes: carbon-12, carbon-13, and carbon-14. which of these statements are true about carbon and its isotopes? select all that appl